- #1
- 1,105
- 1
Greetings !
I'd appreciate some help in explaining, in general,
what - extracting partial differentials of a function, means.
I'm talking about a function like f(x,y,z).
Does it mean that I need a single solution where
I will have differentials for x,y,z of the func.?
Example:
f'(x,y,z) = ( x^2*y + y^2*z + x*e^(2z) )' =
= (2x*y + e^(2z))x' + (x^2 + 2y*z)y' + (y^2 + 2e^(2z))z'
Also (this is related to physics), if I have unit vectors
of x, y, z in the func. do they stay as they were
or does it entail doing some tricks on them as well
(for Cartesian coordinates - I don't think I should touch'em,
but what about a func. of polar coordinates - discribing the
course of the particle itself).
Thanks !
Live long and prosper.
I'd appreciate some help in explaining, in general,
what - extracting partial differentials of a function, means.
I'm talking about a function like f(x,y,z).
Does it mean that I need a single solution where
I will have differentials for x,y,z of the func.?
Example:
f'(x,y,z) = ( x^2*y + y^2*z + x*e^(2z) )' =
= (2x*y + e^(2z))x' + (x^2 + 2y*z)y' + (y^2 + 2e^(2z))z'
Also (this is related to physics), if I have unit vectors
of x, y, z in the func. do they stay as they were
or does it entail doing some tricks on them as well
(for Cartesian coordinates - I don't think I should touch'em,
but what about a func. of polar coordinates - discribing the
course of the particle itself).
Thanks !
Live long and prosper.