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#### find_the_fun

##### Active member

- Feb 1, 2012

- 166

- Thread starter find_the_fun
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- Thread starter
- #1

- Feb 1, 2012

- 166

- Feb 13, 2012

- 1,704

Since for all real x is $ 4\ (x^{2} + 1) > 0$ You can devide both sides by $ 4\ (x^{2} + 1)$ without danger and then integrate separately in x and y...

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$\chi$ $\sigma$

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Since this equation is separable, the best approach would be to divide so that you can separate variables, and as