Hi all,
How should I divide quarter of an ellipse into two equal havles? At what angle should I divide so that the 2 parts are equal?
Any hint is a privilege.
Thanks in advance
Regards
Suji
Now stretch the vertical axis by a factor of \(\displaystyle \frac{a}{b}\) such that the ellipse now becomes a circle of radius $a$. We know the line $y=x$ will divide the first quadrant area of the circle into two equal halves.
Now shrink the vertical axis back to where it started, by a factor \(\displaystyle \frac{b}{a}\), and the dividing line is now:
\(\displaystyle y=\frac{b}{a}x\)
And we see the angle of inclination of this line is: