- #1
snash1057
- 15
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A diverging lens is used to form a virtual image of an object. The object is 88.0 cm in front of the lens, and the image is 44.0 cm in front of the lens. Determine the focal length of the lens.
1/f = 1/do + 1/di
since do is 88cm infront of the lense, that would keep the 88 positive, and since di is 44cm in front of the lense, that would make it negative
so
1/f = 1/88 + 1/-44
1/f = -.011
f= -90.9cm
but its incorrect so if anyone could help correct me thatd be great!
1/f = 1/do + 1/di
since do is 88cm infront of the lense, that would keep the 88 positive, and since di is 44cm in front of the lense, that would make it negative
so
1/f = 1/88 + 1/-44
1/f = -.011
f= -90.9cm
but its incorrect so if anyone could help correct me thatd be great!