Distance traveled by X-rays in air

[Lambduh]

Hi guys new to the forums and have a quick question about x-rays!

I'm guessing that if i know how far an x-ray is traveling in atmosphere from where it is generated before being absorbed (by using a simple x-ray detector) i should be able to calculate the approximate energy of that x-ray. It's a rather crude method and i just want to figure out the general energy, nothing specific. I don't know much about the subject and am curious what i would need to solve this. Thanks!

Mark

 

[vanesch]

There exists an on-line calculator

http://physics.nist.gov/PhysRefData/Xcom/Text/XCOM.html

which gives you the attenuation coefficient in any material composition as a function of the energy of the gamma (or X) ray.

 

[astrokreng]

,

Calculating the distance traveled by X-rays in air is a complex process that involves multiple factors such as the energy of the X-ray, the composition of the air, and the density of the air. It is not a simple calculation and requires a thorough understanding of X-ray physics and atmospheric science.

To estimate the energy of an X-ray based on its distance traveled in air, you would need to know the initial energy of the X-ray, the intensity of the X-ray beam, and the absorption coefficient of air for that particular energy. Even then, the calculation would only provide an approximation as there are many variables that can affect the distance traveled by X-rays in air.

It is important to note that X-rays can travel long distances in air, sometimes even up to several meters, depending on their energy and the density of the air. However, as they travel through air, they lose energy due to interactions with the air molecules. This means that the energy of the X-ray detected at a certain distance from its source may not be the same as its initial energy.

In summary, determining the distance traveled by X-rays in air and using it to estimate their energy is a complex process that requires a deep understanding of X-ray physics and atmospheric science. It is not something that can be accurately done with a simple calculation. I suggest consulting with a qualified scientist or conducting further research to gain a better understanding of this topic. I hope this helps.