- #1
Nemo's
- 69
- 0
Homework Statement
Given a crystal (cube) with regularly arranged atoms (Total 27 atoms)
The mass of each atom is 3.5*10^-25. The density of the crystal is 9.2*10^3
What is the shortest distance between the centres of two adjacent atoms?
Homework Equations
density = mass / volume
The Attempt at a Solution
Volume= (27*3.5*10^-25)/(9.2*10^3)=1.03*10^-27
Length(L)=1*10-9
Distance between two atoms is L/2=5.04*10^-10
Correct answer is 3.4*10^-9