- #1
h0h0
- 2
- 0
The flow defined by a differential equation/general solution
I'm trying to find the 'general solution'(perhaps more accurately the flow)
of the following ODE:
[tex]x' = x(1-x)[/tex]
i.e. [tex]\lambda_{max}(t, \tau,\xi)[/tex] and the domain where it's defined [tex]\Omega[/tex]
note:
The definition of 'general solution' I'm referring to here is the following:
Given a open [tex]D\subset R^{1+N} [/tex], a continuous and with respect to x Lipschitz-continous function [tex]f:D \rightarrow R^{N} [/tex], and the differential equation
[tex]x' = f(t,x)[/tex]
The function [tex]\lambda(t, \tau,\xi) := \lambda_{max}(t, \tau,\xi)[/tex] defined for [tex](t, \tau,\xi)\in\Omega := \left\{(t, \tau,\xi)\inR^{1+1+N} : (\tau,\xi)\in D, t \in I_{max}(\tau,\xi)\right\}[/tex]
is called the 'general solution' of the differential equation.
[tex]\lambda_{max}[/tex] is the maximal solution, and [tex]I_{max}(\tau,\xi)[/tex] the maximal interval of
existence of the solution of the intial value problem [tex]x(\tau)=\xi[/tex]
Any recommended examples/literature?
I'm trying to find the 'general solution'(perhaps more accurately the flow)
of the following ODE:
[tex]x' = x(1-x)[/tex]
i.e. [tex]\lambda_{max}(t, \tau,\xi)[/tex] and the domain where it's defined [tex]\Omega[/tex]
note:
The definition of 'general solution' I'm referring to here is the following:
Given a open [tex]D\subset R^{1+N} [/tex], a continuous and with respect to x Lipschitz-continous function [tex]f:D \rightarrow R^{N} [/tex], and the differential equation
[tex]x' = f(t,x)[/tex]
The function [tex]\lambda(t, \tau,\xi) := \lambda_{max}(t, \tau,\xi)[/tex] defined for [tex](t, \tau,\xi)\in\Omega := \left\{(t, \tau,\xi)\inR^{1+1+N} : (\tau,\xi)\in D, t \in I_{max}(\tau,\xi)\right\}[/tex]
is called the 'general solution' of the differential equation.
[tex]\lambda_{max}[/tex] is the maximal solution, and [tex]I_{max}(\tau,\xi)[/tex] the maximal interval of
existence of the solution of the intial value problem [tex]x(\tau)=\xi[/tex]
Any recommended examples/literature?
Last edited: