Diffusion at a concentration step

In summary, the problem is finding the change in electron density due to diffusion in a cube with known dimensions and constant electron density n. All relevant parameters including temperature and the diffusion constant are also known. The question is asking for the diffusion current, represented by \frac{dn}{dt} . Fick's Law may not be applicable due to the steep concentration gradient from n inside to 0 outside the device, but the hint suggests there may be another useful equation to use.
  • #1
Otterhoofd
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Homework Statement


You have a solar cell with a constant electron density n, and known dimensions. I am looking for the change in density due to diffusion, so basically the diffusion current. All other relevant parameters are also known (temperature, D diffusion constant, etc.)

To summarize the problem: I have a cube with electron density n, outside electron density 0. Question: what is [itex] \frac{dn}{dt} [/itex] due to diffusion?

Homework Equations


Fick's Law: [itex] J = - D \times \frac{dn}{dx} [/itex]
Or root mean square distance traveled by brownian motion:
[itex] \Delta x_{rms} = \sqrt{2\times D \times t} [/itex]

The Attempt at a Solution


Using Fick's law, you get a infinite current since there is a concentration step from n inside to 0 outside the device. However, i think that Ficks law does not hold for this steep concentration gradients. Maybe one could solve this using equipartition of energy? But then again, the exercise hints at the use of the diffusion parameter and says the question should be simple to answer.

Any help would be greatly appreciated. Thank you.
 
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  • #2
Hint: There's a more useful equation than Fick's first law.
 

1. What is diffusion at a concentration step?

Diffusion at a concentration step is the movement of particles from an area of high concentration to an area of low concentration, across a concentration gradient. This process occurs in order to reach a state of equilibrium, where the concentration of particles is equal on both sides of the gradient.

2. How does diffusion at a concentration step occur?

Diffusion at a concentration step occurs due to the random motion of particles, also known as Brownian motion. As particles move, they collide with one another and with the walls of their container, causing them to spread out and move from areas of high concentration to areas of low concentration.

3. What factors affect diffusion at a concentration step?

The rate of diffusion at a concentration step can be affected by several factors, including temperature, size of the particles, and the concentration gradient. Higher temperatures and smaller particle sizes typically result in faster diffusion, while a larger concentration gradient (difference in concentration between areas) can also increase the rate of diffusion.

4. What are some real-world examples of diffusion at a concentration step?

One common example of diffusion at a concentration step is the process of perfume spreading throughout a room. The perfume particles move from an area of high concentration (the bottle) to an area of low concentration (the rest of the room) until they are evenly distributed. Another example is the movement of oxygen and carbon dioxide in and out of our cells during respiration.

5. How is diffusion at a concentration step different from osmosis?

Diffusion at a concentration step and osmosis are both forms of passive transport, meaning they do not require energy. However, diffusion at a concentration step involves the movement of particles across a concentration gradient, while osmosis specifically refers to the diffusion of water molecules across a selectively permeable membrane. Additionally, osmosis only occurs with water, while diffusion at a concentration step can involve any type of particle.

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