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The Erdos-Straus Conjecture proposes that:
For n >= 1, 4/n = 1/a + 1/b + 1/c, has postive integer solutions.
n = 2k (evens)
n = 4k+3 (odds)
n = 4k+1 (odds)
For 2k I have found the pattern --> if k >= 1, 4/2k = 1/2k + 1/2k + 1/k. This is simple, I know.
I am having difficulty finding the pattern for 4k+3 (no pattern has yet been found for 4k+1, I know).
So what is the pattern for:
4/4k+3 = 1/a + 1/b + 1/c
?
Does anyone know this pattern? If you do, please reply with such pattern.
Thank you
J.E.H.
For n >= 1, 4/n = 1/a + 1/b + 1/c, has postive integer solutions.
n = 2k (evens)
n = 4k+3 (odds)
n = 4k+1 (odds)
For 2k I have found the pattern --> if k >= 1, 4/2k = 1/2k + 1/2k + 1/k. This is simple, I know.
I am having difficulty finding the pattern for 4k+3 (no pattern has yet been found for 4k+1, I know).
So what is the pattern for:
4/4k+3 = 1/a + 1/b + 1/c
?
Does anyone know this pattern? If you do, please reply with such pattern.
Thank you
J.E.H.