- #1
PhyAmateur
- 105
- 2
We have this stationary metric, $$ds^2 = e^{2U}(dt+\omega_idx^i)^2 -e^{-2U}dx^2$$
The book wrote down the spin connections of this:
$$ \omega^{0i}=\partial_ie^{U}e^0 +e^{3U}\partial_{[_i\omega _k]}e^k $$
and $$ \omega^{ij}= e^{3U}(\partial_{[_i\omega _j]}e^0-\partial_{[_ie^{-2U}\delta_j]k} )$$
it is this $$ \partial_{[_i\omega _j]}$$ that I didn't understand along with the $$\partial_{[_ie^{-2U}\delta_j]k}$$ . If we unwrapped these, what do we get? I am only having problem with the notation.
Note please that the book mentioned that $$\partial_{[_i\omega _j]}= - \frac{1}{2} \epsilon _{ijk}\partial_kb$$ where I have no idea what he meant by b. The first time I saw this b was in this note.
{I can attach the page of the book if needed (if my writings here are not clear as upper indices or lower ones).}
The book wrote down the spin connections of this:
$$ \omega^{0i}=\partial_ie^{U}e^0 +e^{3U}\partial_{[_i\omega _k]}e^k $$
and $$ \omega^{ij}= e^{3U}(\partial_{[_i\omega _j]}e^0-\partial_{[_ie^{-2U}\delta_j]k} )$$
it is this $$ \partial_{[_i\omega _j]}$$ that I didn't understand along with the $$\partial_{[_ie^{-2U}\delta_j]k}$$ . If we unwrapped these, what do we get? I am only having problem with the notation.
Note please that the book mentioned that $$\partial_{[_i\omega _j]}= - \frac{1}{2} \epsilon _{ijk}\partial_kb$$ where I have no idea what he meant by b. The first time I saw this b was in this note.
{I can attach the page of the book if needed (if my writings here are not clear as upper indices or lower ones).}