- #1
sozener1
- 19
- 0
I asked to differentiate the given function using exponential function
with sin(√3t + 1) I turned it into Im[e^(√3t+1)i]
then I multiplied it by e^t
which gave Im[e^t*e^(√3t +1)i]
then I applied usual algebra to differentiate but I get a (t+√3ti +i) as the power of e
when I try to differentiate (t+√3ti +i) with respect to t I can do it with the first two terms but not i
how do you do differentiation over i? does it go to zero??
with sin(√3t + 1) I turned it into Im[e^(√3t+1)i]
then I multiplied it by e^t
which gave Im[e^t*e^(√3t +1)i]
then I applied usual algebra to differentiate but I get a (t+√3ti +i) as the power of e
when I try to differentiate (t+√3ti +i) with respect to t I can do it with the first two terms but not i
how do you do differentiation over i? does it go to zero??