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#### Alexmahone

##### Active member

- Jan 26, 2012

- 268

Differentiate $x^{1/2}\left[c_1J_{1/4}(x^2/2)+c_2J_{-1/4}(x^2/2)\right]$.

- Thread starter Alexmahone
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- Thread starter
- #1

- Jan 26, 2012

- 268

Differentiate $x^{1/2}\left[c_1J_{1/4}(x^2/2)+c_2J_{-1/4}(x^2/2)\right]$.

- Feb 13, 2012

- 1,704

A general formula is...Differentiate $x^{1/2}\left[c_1J_{1/4}(x^2/2)+c_2J_{-1/4}(x^2/2)\right]$.

$\displaystyle J_{\nu}^{'}(x)= \frac{1}{2}\ \{J_{\nu-1}(x)-J_{\nu+1}(x)\}$ (1)

Kind regards

$\chi$ $\sigma$