- #1
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Homework Statement
According to my math book, I solved the following trig equation correctly:
1)
cos3x=0,500=
3x = 60° + n360°
x=20+n120°
2)I also solved this problem correctly:
4sin^2x -3sin^x= 0
sinx(4sinx-3)=0
x=n*360°
or
4sinx=3
sinx=3/4
x= ca. 49°
x=49° + n360° or 131+ n360°.
Now I´m wondering why I can´t solve question nr 1) in the following way:
cosx = 0,500/3
x=80°
x=80° + n360°
i.e. why can´t I solve question nr 1 the way I did question nr 2?
I was also wondering if sin2x is the same as 2sinx? does it make a difference where I place the 2?
Homework Equations
NA
The Attempt at a Solution
see above