Differences between equations of SHM

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In summary, the y function is a sine wave and the x function is a cosine wave because for circular motion, the two components must be out of phase. This is because the acceleration for SHM needs to be directly proportional to the displacement, and the second derivative of sine is equal to negative cosine. The two equations are fundamentally correct, but differ by a phase of pi/2, which corresponds to a difference in initial conditions. The cosine and sine functions are interchangeable due to the phase difference of pi/2.
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castor
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Why is it that ## y = A\sin (\omega t + \phi) ## whereas ## x = A\cos (\omega t + \phi) ##?

Why is it that the y function is a sine wave, whereas the x function a cosine wave? I'm sorry if this question sounds ridiculous.
 
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is this circular motion? for SHM it doesn't matter if you use cosine or sine. for circular motion it's because the two components have to be out of phase. if you used both cosine or both sine, then the particle would oscillate back and forth on the line y=x
 
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  • #3
castor said:
Why is it that y=Asin(ωt+ϕ)
because y'' = acceleration and for SHM i needs to be directly proportional to -y(displacement)
and it happens to be that second derivative of sine is ''-''cosine !
otherwise both equations are fundamentally correct
 
  • #4
If you plot the 2 solutions you will see that they differ by a phase of pi / 2 . This corresponds to a difference in starting position, or the location of the "bob" when you start the clock. So mathematically these are 2 solutions to the same differential equation resulting from different initial conditions.
 
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Shreyas Samudra said:
because y'' = acceleration and for SHM i needs to be directly proportional to -y(displacement)
and it happens to be that second derivative of sine is ''-''cosine !
otherwise both equations are fundamentally correct

The same can be said for the x function; x" = - acceleration, isn't it?

## x = A\cos (\omega t + \phi) ##
## x' = - A\omega\sin (\omega t + \phi) ##
## x'' = - A\omega^2\cos (\omega t + \phi) ##
## x'' = - \omega^2 (A\cos (\omega t + \phi)) ##
## x'' = - \omega^2 x ##

No, the only thing I'm asking is that why is the y function a sine wave, and the x component a cosine wave? Is it, as Integral said, just an example of the two functions having two initial conditions that have a phase difference of ##\frac{\pi}{2}##?
 
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  • #7
castor said:
Why is it that y=Asin(ωt+ϕ) y = A\sin (\omega t + \phi) whereas x=Acos(ωt+ϕ) x = A\cos (\omega t + \phi) ?

There is no relation between the two equations - first is along y-axis direction and other along x-axis .

If your question is why one uses cosine and other sine , the cos and sin are interchangeable due to the phase φ by + - π/2 ( changing φ at the same time ) .
 
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Qwertywerty said:
There is no relation between the two equations - first is along y-axis direction and other along x-axis .

If your question is why one uses cosine and other sine , the cos and sin are interchangeable due to the phase φ by + - π/2 ( changing φ at the same time ) .
Right, thanks for clearing that up! :)
 

Related to Differences between equations of SHM

What is the equation for simple harmonic motion?

The equation for simple harmonic motion is x = A sin(ωt + φ), where x is the displacement, A is the amplitude, ω is the angular frequency, and φ is the phase angle.

What is the difference between angular frequency and frequency in SHM equations?

Angular frequency (ω) is the rate at which the object completes one full cycle of motion, while frequency (f) is the number of cycles completed per unit time. They are related by the equation ω = 2πf.

What is the role of amplitude in SHM equations?

The amplitude (A) represents the maximum displacement of the object from its equilibrium position. It determines the size of the oscillations and affects the energy of the system.

How does the phase angle affect the motion in SHM equations?

The phase angle (φ) represents the initial position of the object at t=0. It determines where the object starts its motion in relation to the equilibrium position and affects the timing of the oscillations.

What are the different types of SHM equations?

The different types of SHM equations include displacement (x), velocity (v), and acceleration (a) equations. They are related by the fact that acceleration is proportional to displacement and opposite in direction, velocity is proportional to displacement and in phase, and displacement is the integral of velocity.

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