Jan 1, 2014 Thread starter #1 B bergausstein Active member Jul 30, 2013 191 is this a difference of two squares? $\displaystyle x^{\frac{1}{4}}-y^{\frac{1}{4}}$
Jan 1, 2014 Admin #2 M MarkFL Administrator Staff member Feb 24, 2012 13,775 Yes, if you write it as: \(\displaystyle \left(x^{\frac{1}{8}} \right)^2-\left(y^{\frac{1}{8}} \right)^2\)
Yes, if you write it as: \(\displaystyle \left(x^{\frac{1}{8}} \right)^2-\left(y^{\frac{1}{8}} \right)^2\)
