Difference between omega 0 and omega k

In summary, there are two terms commonly used in cosmology literature to represent the curvature or flatness of the universe: omega sub zero and omega k. These terms can be confusing, but they have distinct meanings. Omega sub zero represents the ratio of the actual density to the critical density, while omega k represents the curvature of the universe. In a flat universe, omega sub zero would equal 1 and omega k would equal 0. Different references may use different notations, so it is important to clarify which term is being used in a given context.
  • #1
windy miller
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As I try and read cosmology literature with the eyes of layman , I find two different terms that seem to represent the curvature ( or lack of) of the universe .
These are omega sub zero and omega k. But I can't see the difference between the two. Can anyone explain this?
 
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  • #3
mathman said:
you may be confusing terms. [itex]\Omega [/itex] is usually to represent the density of the universe, normalized so that = 1 means flat.

Yes, but ##\Omega_k## (not an actual mass/energy density) often is defined as ##\Omega_k = 1 - \Omega##, so that ##\Omega_k = 0## for a spatially flat universe.

I though that ##\Omega_0## usually means ##\Omega_0 = \Omega \left(t_0\right)##, i.e., ##\Omega_0## is the value of the total relative density right now, but I could be wrong. Also, different references can use different notations.
 
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  • #4
Interestingly in the
George Jones said:
Yes, but ##\Omega_k## (not an actual mass/energy density) often is defined as ##\Omega_k = 1 - \Omega##, so that ##\Omega_k = 0## for a spatially flat universe.

I though that ##\Omega_0## usually means ##\Omega_0 = \Omega \left(t_0\right)##, i.e., ##\Omega_0## is the value of the total relative density right now, but I could be wrong. Also, different references can use different notations.

I get the impression that omega k is the curvature so 0 means zero curvature, whereas omega sub zero is the ratio of the critical density to the actual density and so with zero curvature omega sub zero should be 1. Is that correct?
 
  • #5
windy miller said:
I get the impression that omega k is the curvature so 0 means zero curvature, whereas omega sub zero is the ratio of the critical density to the actual density and so with zero curvature omega sub zero should be 1. Is that correct?

The ratio is the other way around, .i.e., ##\Omega## is the ratio of the actual density to the critical density. If the present time is ##t_0##, then ##\Omega_0 = \Omega\left(t_0\right)##, and if at time ##t_0## the universe is spatially flat, then, yes, ##\Omega_0 = 1##.
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Related to Difference between omega 0 and omega k

1. What is the difference between omega 0 and omega k?

The terms omega 0 and omega k refer to two different parameters in the field of cosmology. Omega 0, also known as the density parameter, is the ratio of the actual density of the universe to the critical density. On the other hand, omega k, also known as the curvature parameter, is a measure of the curvature of the universe. In simple terms, omega 0 tells us how much matter and energy the universe contains, while omega k tells us about the shape of the universe.

2. How are omega 0 and omega k related?

The relationship between omega 0 and omega k is described by the Friedmann equations, which are used to model the expansion of the universe. These equations show that the sum of omega 0 and omega k must equal to 1 in a flat universe. In other words, if omega 0 is greater than 1, the universe is closed and has a positive curvature. If omega 0 is less than 1, the universe is open and has a negative curvature. If omega 0 equals 1, the universe is flat. Omega k, therefore, complements omega 0 in determining the overall geometry of the universe.

3. How do omega 0 and omega k affect the fate of the universe?

The values of omega 0 and omega k have a significant impact on the fate of the universe. If omega 0 is greater than 1, the universe will eventually stop expanding and start contracting in a "Big Crunch." If omega 0 is less than 1, the universe will continue to expand forever. If omega 0 equals 1, the universe will reach a state of equilibrium and stop expanding. On the other hand, omega k determines the overall curvature of the universe and whether it is open or closed. A positive omega k indicates a closed universe, while a negative omega k indicates an open universe.

4. How do scientists measure omega 0 and omega k?

Scientists use various methods to measure the values of omega 0 and omega k. One common method is through observations of the cosmic microwave background (CMB). The CMB is the leftover radiation from the early universe, and by studying its properties, scientists can estimate the values of omega 0 and omega k. Other methods include measuring the large-scale structure of the universe, such as the distribution of galaxies, and studying the expansion rate of the universe through supernovae observations.

5. Is there a preferred value for omega 0 and omega k?

There is no preferred value for omega 0 and omega k, as they are both dependent on the overall structure and content of the universe. However, current measurements of these parameters suggest that the universe is very close to being flat, with an omega 0 value of around 1. This means that the universe contains just enough matter and energy to balance out the expansion and keep it flat. As for omega k, recent data suggests that it is very close to 0, indicating that the universe is flat and has no overall curvature.

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