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Dice Problem

veronica1999

Member
Jun 4, 2012
63
Five standard 6-sided dice are rolled. What is the probability that at least 3 of them show a six?

I am surprised my answer is wrong.

First the total outcomes are 6x6x6x6x6=7776

Successful outcomes 10x6x6=360
There are 10 ways to choose 3 from 5 and then the remaining 2 can be any number.

360/7776 is not the answer.

The answer is 276/7776.:confused:
 

Opalg

MHB Oldtimer
Staff member
Feb 7, 2012
2,702
Re: dice problem

Five standard 6-sided dice are rolled. What is the probability that at least 3 of them show a six?

I am surprised my answer is wrong.

First the total outcomes are 6x6x6x6x6=7776

Successful outcomes 10x6x6=360
There are 10 ways to choose 3 from 5 and then the remaining 2 can be any number.

360/7776 is not the answer.

The answer is 276/7776.:confused:
You have double-counted the ways in which four or five sixes can occur. What you should do is to count the number of ways in which exactly three sixes can occur (10x5x5), then add the number of ways in which four sixes can occur (5x5), and finally the one way in which five sixes can occur.
 

veronica1999

Member
Jun 4, 2012
63
Re: dice problem

Oops....
Thanks!!!!!:D
 

MarkFL

Administrator
Staff member
Feb 24, 2012
13,775
Re: dice problem

I would use the complements rule:

\(\displaystyle P(X)=1-\frac{{5 \choose 0}5^5+{5 \choose 1}5^4+{5 \choose 2}5^3}{6^5}=\frac{23}{648}\)