DFT Symmetry Property: Why Does the Answer Not Void This Property?

In summary, the DFT of x[n]={1,1,0,1} results in X(m)={3,1,-1,1}, which follows the symmetry property where X_k=\bar{X}_{N-k} for real data. This holds true in the given example for N=4.
  • #1
Shaheers
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Homework Statement



As an example, if we find a DFT of x[n]={1,1,0,1}
the result will be X(m)={3,1,-1,1}


Homework Equations



My Question is that as we know DFT holds symmetry property, why this answer does not void for that property?
 
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  • #2
Let's take the definition from Wikipedia:
[tex]X_k=\sum_{n=0}^{N-1}x_n\,e^{-i2\pi kn/N}[/tex]
For real data you have then the symmetry:
[tex]X_k=\bar{X}_{N-k},\, (k=1,...,N).[/tex]
In your case [itex]N=4[/itex], and you have [itex]X_0=3,X_1,=1,X_2=-1,X_3=1,[/itex] all real.

From the symmetry property you should have [itex]X_4=X_0,X_3=X_1,X_2=X_2[/itex].
And you have it ([itex]X_4[/itex] can be thought of as defined by the symmetry property).
 
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Related to DFT Symmetry Property: Why Does the Answer Not Void This Property?

1. What is the DFT symmetry property?

The DFT (Discrete Fourier Transform) symmetry property states that the complex Fourier coefficients of a real-valued signal have symmetric and anti-symmetric components. This means that the even components of a signal are represented by the real part of the coefficients, while the odd components are represented by the imaginary part of the coefficients.

2. Why is the DFT symmetry property important?

The DFT symmetry property is important because it allows us to efficiently compute the Fourier transform of a real-valued signal by only calculating half of the coefficients. This reduces the computational complexity and makes the DFT a more practical tool for analyzing real-world signals.

3. How is the DFT symmetry property related to the Nyquist frequency?

The DFT symmetry property is closely related to the Nyquist frequency, which is the maximum frequency that can be accurately represented in a digital signal. The Nyquist frequency is equal to half the sampling frequency, which corresponds to the point where the complex Fourier coefficients switch from symmetric to anti-symmetric.

4. Can the DFT symmetry property be applied to non-periodic signals?

No, the DFT symmetry property only applies to periodic signals. For non-periodic signals, the DFT coefficients are not symmetric and do not have the same properties as those of periodic signals.

5. How does the DFT symmetry property affect the interpretation of frequency spectra?

The DFT symmetry property affects the interpretation of frequency spectra by reducing the number of unique frequency components that need to be considered. This is because the symmetric and anti-symmetric components are essentially mirror images of each other, so only half of the coefficients need to be analyzed to obtain the complete frequency spectrum. Additionally, the symmetry property allows for a more intuitive understanding of the frequency spectrum, as the even and odd components represent different aspects of the signal.

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