- #1
mom2maxncoop
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Homework Statement
The mass of the piece of ice is 0.25kg.
Heated by an electric heater (assume there is no loss of energy to the surroundings)
Started at -30°C at 0seconds
After 150s the ice cube is -10°C
Homework Equations
Q=mL[itex]_{f}[/itex]
[itex]\Delta[/itex]t=Q[itex]/[/itex]P
The Attempt at a Solution
Q=mL[itex]_{f}[/itex]
=(0.25kg)(330000J/(kg·°C)
=82500J
I know the next step is to use the second equation, but since I don't know the W of the heater, how would I go abouts finding out the time??