DennisG said:An electron in the hydrogen atom makes a transition from an energy state of principle quantum number N(i) to the N=2 state. If the photon emitted has a wavelength of 434 nm, what is the value of N(i)?
...no idea
DennisG said:An electron in the hydrogen atom makes a transition from an energy state of principle quantum number N(i) to the N=2 state. If the photon emitted has a wavelength of 434 nm, what is the value of N(i)?
...no idea
N(i) refers to the initial energy level of an electron in a hydrogen atom before it transitions to a lower energy level. It is represented by the principal quantum number, n.
N(i) can be determined by analyzing the spectral lines produced when an electron transitions from a higher energy level to a lower one. The energy of each line is directly related to the initial energy level of the electron.
Determining N(i) allows us to understand the energy levels of electrons in a hydrogen atom and how they transition between levels. This information is crucial in many fields, including atomic and molecular physics, spectroscopy, and quantum mechanics.
Yes, N(i) can be calculated using the Rydberg formula, which relates the energy levels of the electron to the spectral lines produced. This allows us to determine the principal quantum number, n, and therefore the initial energy level of the electron.
In the Bohr model of the atom, N(i) is represented by the principal quantum number, n, which determines the size and energy of the electron's orbit. Higher values of n correspond to higher energy levels, and as the electron transitions to lower levels, n decreases, and the energy decreases.