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Homework Statement
MgSO4*xH20
mass of hydrated comlex (g) - 6.32
mass of anhydrous complex (g) - 3.54
mass of water (g) - 2.78
MolarMass MgSO4 = 120.38g/mol
MolarMass H2O = 18.02g/mol
Based on those results, determine the molecular formula of the hydrate.
Homework Equations
n=m/M
The Attempt at a Solution
nMgSO4 = 3.54/120.38 ---> 0.0294068782189733
nH2O = 2.78/18.02 ----> 0.1542730299667037
then to find the multiplier I must divide by the lowest mol;
0.0294068782189733/0.0294068782189733 = 1
0.1542730299667037/0.0294068782189733 = 5.246154617907276 / 5.25
therefore, for every MgSO4, there is 5.25H2O
Molecular formula: Mg4SO16*21H2O (since our teacher asks for integers only)
is this correct, or is it incorrect, help please!