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killaI9BI
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Homework Statement
This problem has had me puzzled for hours. I really appreciate any help you can provide.
A light plane leaves Shelburne, NS and flies 195km [N15°W] to Saint John, NB. After picking up a passenger, it flies to Moncton, NB which is 149km [N33°E]. The entire trip took 3.75h.
Calculate the average velocity of the plane for the entire trip from Shelburne, NS to Moncton, NB.
Homework Equations
a2 + b2 = c2
tan Θ = y-coordinates/x-coordinates
The Attempt at a Solution
dsjx = (-195) X cos75 = (-50.47)km W
dsjy = 195 X sin75 = 188.36km N
dmx = 149 X cos57 = 81.15km E
dmy = 149 X sin57 = 124.96km N
dx = (-50.47) + 81.15 = 30.68km E
dy = 188.36 + 124.96 = 313.32km N
r2 = 30.682 + 313.322
r2 = 99110.68
r = 314.8
314.8/3.75 = 83.95/h
tan θ = 313.32/30.68 = 10.21
θ = 84.4
The average velocity is 84km/h W 84 N.
The books answer is 48km/h [W29°N]