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- Feb 14, 2012

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$\displaystyle \sin^{23}\left(\frac{A}{2}\right) \cos^{48} \left(\frac{B}{2}\right)=\sin^{23} \left(\frac {B}{2}\right) \cos^{48} \left(\frac {A}{2}\right)$

Determine the value of $\dfrac {AC}{BC}$.

Hi all, the huge values of the exponents make me cringe to try to solve the problem. I want to ask if this is obvious that one of the possibilities is that the given equality is true iff the measures of both the angles A and B are equal. Is this true? That is, we're dealing with an isosceles triangle where $\dfrac {AC}{BC}=1$?