Determine the equilibrium pH of aqueous solutions for the following strong acids

In summary: Members are not allowed to help with homework (which is what this is).In summary, the equilibrium pH of aqueous solutions can be determined using the respective Ka values for strong acids and bases. For (a) 257mg/L of HSO4-, the pH can be calculated by considering the hydrolysis of HSO4-. However, for (b) 10nM NaOH, this exercise is nonsensical as the concentration of carbon dioxide/bicarbonate would have a significant impact on the results. As for (c) 75ug/L of HNO3, its pH can be calculated using the Ka value for nitric acid.
  • #1
tobyracine
3
0
Determine the equilibrium pH of aqueous solutions for the following strong acids or bases: (a) 257mg/L of HSO4- ; (b) 10nM NaOH ; (c) 75ug/L of HNO3
 
Physics news on Phys.org
  • #2
Look for their respective Ka values on net.
 
  • #3
I kind of figured it out except for the first one, because HSO4- can become an acid or a base depending what it's mixed with so I don't know what to do, do I get the pH or the pOH? And how?
 
  • #5
Thanks
 
  • #6
Not totally relevant to the OP, but part (b) of this exercise is nonsensical in any practical terms. I bring this up because we are in the "Chemistry" forum rather than the "Chemistry Homework" forum.

The answer to a formal calculation to part (b) will only bear any relationship to reality if the concentration of carbon dioxide/bicarbonate in the water is much smaller than that of the hydroxyl -- say 1 nM or less. Any normal aqueous solution will be acting as a carbonate buffer for such low levels of hydroxyl, and I would like to know how anyone proposes to prepare a water sample that is accessible for normal laboratory work, but less than 1 nM in bicarbonate/carbon dioxide.
 
  • #7
It is a typical trick question asked every year :smile:

And heck, you are right about homework... Moving the thread.

toby: please read forum rules.
 

Related to Determine the equilibrium pH of aqueous solutions for the following strong acids

1. What is a strong acid?

A strong acid is a chemical compound that completely dissociates in water, producing a high concentration of hydrogen ions (H+) and a low concentration of hydroxide ions (OH-). This results in a low pH value (below 7) in aqueous solutions.

2. How is the equilibrium pH of a strong acid solution determined?

The equilibrium pH of a strong acid solution is determined by the concentration of the acid and its dissociation constant, which is a measure of the strength of the acid. It can be calculated using the Henderson-Hasselbalch equation: pH = -log([H+]), where [H+] is the concentration of hydrogen ions in the solution.

3. What factors can affect the equilibrium pH of a strong acid solution?

The equilibrium pH of a strong acid solution can be affected by the concentration of the acid, temperature, and the presence of other substances that can interact with the acid. Additionally, changes in pressure or dilution of the solution can also impact the equilibrium pH.

4. How does the equilibrium pH of a strong acid solution compare to that of a weak acid solution?

The equilibrium pH of a strong acid solution is lower than that of a weak acid solution, as strong acids dissociate completely in water while weak acids only partially dissociate. This means that strong acids have a higher concentration of hydrogen ions, resulting in a lower pH value.

5. Can the equilibrium pH of a strong acid solution be lower than 0 or higher than 14?

No, the equilibrium pH of a strong acid solution cannot be lower than 0 or higher than 14. The pH scale ranges from 0 to 14, with 0 being the most acidic and 14 being the most basic. A strong acid solution can have a pH value close to 0, but it cannot go below 0. Similarly, it can have a pH value close to 14, but it cannot go above 14.

Similar threads

  • Biology and Chemistry Homework Help
Replies
6
Views
2K
  • Biology and Chemistry Homework Help
Replies
3
Views
2K
  • Biology and Chemistry Homework Help
Replies
7
Views
2K
  • Biology and Chemistry Homework Help
Replies
5
Views
3K
  • Biology and Chemistry Homework Help
Replies
2
Views
2K
  • Biology and Chemistry Homework Help
Replies
12
Views
3K
  • Biology and Chemistry Homework Help
Replies
16
Views
2K
  • Biology and Chemistry Homework Help
2
Replies
48
Views
7K
  • Biology and Chemistry Homework Help
Replies
2
Views
4K
  • Biology and Chemistry Homework Help
Replies
1
Views
1K
Back
Top