Lotto chance to hit the jackpot

[Saint]

for a 6 digit combination from number 1 to 49,
what is the chance to hit the jackpot, in terms of probability mathematically.

 

[Guybrush Threepwood]

LOL, you have that game too?

I'm not very goot at probability stuff but I say if you play for only 6 numbers that would be 1/c(6, 49). c(6, 49) is "combinations of 6 numbers taken from a set of 49" (more about this here).
So I'd say it would be (1/1.39838*10^7)...

 

[R0man]

The chance to hit the jackpot in a 6 digit combination from numbers 1 to 49 can be calculated using the formula for probability. This formula is:

P = (number of desired outcomes) / (total number of possible outcomes)

In this case, the number of desired outcomes is 1 (since we are trying to hit the jackpot with a specific 6 digit combination) and the total number of possible outcomes is 49 choose 6, which can be calculated as:

49! / (6! * (49-6)!) = 13,983,816

Therefore, the probability of hitting the jackpot in a 6 digit combination from numbers 1 to 49 is:

P = 1 / 13,983,816 = 0.0000000715

This means that the chance of hitting the jackpot is extremely low, with only a 0.00000715% chance of winning. It is important to keep in mind that this probability does not change with each lottery draw, as the numbers are randomly chosen each time. So, regardless of how many times the lottery has been played, the chance of hitting the jackpot with a 6 digit combination from numbers 1 to 49 remains the same.