# Determinants

#### Yankel

##### Active member
Hello

I have a question, I think I solved it, and I would like to confirm...

Let A be a 4X4 matrix with and let rank(A)=4.
It is known that det(A^2) = det(-A)
Is det(A)=-1 ?

I think the answer is no.

det(A)*det(A)=det(-A)
det(A)*det(A)=(-1)^4 * det(A) = det(A)
det(A)*det(A) = det(A)

this is true only when det(A)=1 or det(A)=0. The later can't be since rank(A)=4, so det(A)=1. Am I correct ? #### CaptainBlack

##### Well-known member
Hello

I have a question, I think I solved it, and I would like to confirm...

Let A be a 4X4 matrix with and let rank(A)=4.
It is known that det(A^2) = det(-A)
Is det(A)=-1 ?

I think the answer is no.

det(A)*det(A)=det(-A)
det(A)*det(A)=(-1)^4 * det(A) = det(A)
det(A)*det(A) = det(A)

this is true only when det(A)=1 or det(A)=0. The later can't be since rank(A)=4, so det(A)=1. Am I correct ? For a matrix $$\bf{A}$$ of dimension $$2n\times 2n,\ n \in \mathbb{N}_+$$: $$\det(-{\bf{A}})=\det({\bf{A}})$$.

So you have the equality $$[\det({\bf{A}})]^2=\det({\bf{A}})$$, and also $$\det({\bf{A}}) \ne 0$$

CB

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