Deriving the Compton Effect Equation: A System of Equations Approach

In summary, the task at hand is to derive the equation for the Compton Effect from the equations for momentum and energy conservation. This involves a system of equations that can be solved by eliminating squared equations and using identity relationships. By combining quantities and keeping track of constant factors, the derivation can be simplified and the Compton Effect equation can be obtained successfully.
  • #1
eje5758
1
0

Homework Statement


I need to derive the equation related to the Compton Effect from the equations for momentum and energy conservation.

Homework Equations


(1) Compton Effect: λ' -λ = h/me(1-cosθ)
(2) Conservation of Momentum (x-direction): h/λ= (h/λ')cosθ+γumeucosΦ
(3) Conservation of Momentum (y-direction): 0= (h/λ')sinθ+γumeusinΦ
(4) Conservation of Energy: h(c/λ)+mec2 = h(c/λ')+γumec2

Where,
λ=initial wavelength of a photon
λ'= final wavelength of a photon
θ= the angle in which an electron scatters
Φ= the angle in which the photon scatters
u= speed at which electron scatters
c= speed of light in a vacuum

The Attempt at a Solution


This is a system of equations problem. So I approached the problem by eliminating squaring equations (2) and (3) and eventually eliminating Φ. This gave me [(h/λ-hcosθ/λ')2+ (h2sin2θ)/(λ')2]/γum2u2=1

Things started to get realllly messy from here. I successfully eliminated u, but by that time, the algebra was too far gone to get back to the Compton Effect equation. Any help would be appreciated.
 
Physics news on Phys.org
  • #2
The derivation should not be too messy if you kept track of all the constant factors correctly. you might help yourself by for example combining quantities as h/m0cλ into one symbol say α. Just use care in writing down each expression and persist. Leave the cosines alone and rely on identity relationships to simplify the expressions.
 

Related to Deriving the Compton Effect Equation: A System of Equations Approach

What is the Compton Effect and why is it important?

The Compton Effect is a phenomenon in physics where the wavelength of a photon is increased after interacting with a charged particle, such as an electron. This effect was discovered by Arthur Compton in 1923 and is important because it provided evidence for the particle nature of light and helped to advance our understanding of quantum mechanics.

How is the Compton Effect derived mathematically?

The Compton Effect can be derived using the principles of conservation of energy and momentum. By considering the energy and momentum of the photon before and after the interaction with the electron, we can derive an equation that relates the change in wavelength of the photon to the scattering angle of the electron.

What are the assumptions made in deriving the Compton Effect equation?

The derivation of the Compton Effect equation assumes that the photon is a particle with a discrete energy and momentum, and that the electron is a free particle with a known mass and charge. It also assumes that the interaction between the photon and electron is elastic, meaning that no energy is lost during the interaction.

How does the Compton Effect support the wave-particle duality of light?

The Compton Effect provides evidence for the wave-particle duality of light by showing that light exhibits both wave-like and particle-like behavior. The scattering of photons by electrons behaves like particles, while the change in wavelength of the photons behaves like waves.

What are some real-world applications of the Compton Effect?

The Compton Effect has many real-world applications, including medical imaging techniques such as computed tomography (CT) scans and positron emission tomography (PET) scans, as well as airport security scanners. It is also used in materials science to study the structure of materials and in astronomy to measure the properties of celestial objects.

Similar threads

Replies
8
Views
1K
  • Introductory Physics Homework Help
Replies
1
Views
1K
  • Introductory Physics Homework Help
Replies
2
Views
6K
  • Introductory Physics Homework Help
Replies
5
Views
1K
  • Introductory Physics Homework Help
Replies
1
Views
2K
Replies
3
Views
683
  • Introductory Physics Homework Help
Replies
3
Views
869
  • Introductory Physics Homework Help
Replies
9
Views
1K
  • Introductory Physics Homework Help
Replies
8
Views
3K
Replies
1
Views
9K
Back
Top