Deriving Covariance between S and N: E(SN) - ìXìN

In summary, we have a model for aggregate claim amounts, where the individual claim amounts are represented by independent, identically distributed random variables. The number of claims is also a random variable, independent of the individual claim amounts. The mean of the individual claim amounts is \mu_X, while the mean and variance of the number of claims are \mu_N and \sigma^2_N, respectively. By considering expected values conditional on the value of N, we can show that E(SN) = \mu_X (\mu^2_N + \sigma^2_N). This allows us to derive an expression for the covariance between S and N.
  • #1
johnnytzf
3
0
consider the following model for aggregate claim amounts S:
S=X1+X2+...+XN
where the Xi are independent, identically distributed random
variables representing individual claim amounts and N is a random
variable,independent of the Xi and representing the number of
claims.let X has ìx and let N has mean ìN and variance ó²N.

a) show that E(SN)=ìX ( ì²N + ó²N ) by considering expected values
conditional on the value of N

b) hence derive an expression for the covariance between S and N.



I know that

E(S) = E(E(S|N)) = E(N)E(S) = ìXìN,
Var(E(S|N)) = Var(N)Var(S) = ó²Xó²N

but how to link it with E(SN)??
 
Physics news on Phys.org
  • #2
Let's make the question more readable. (See post #3 in the thread https://www.physicsforums.com/showthread.php?t=617567)

Is it this?:

Consider the following model for aggregate claim amounts [itex] S [/itex]
[itex] S=X_1+X_2+...+X_N [/itex]
where the [itex] X_i [/itex] are independent, identically distributed random
variables representing individual claim amounts and [itex] N [/itex] is a random
variable,independent of the [itex] X_i [/itex] and representing the number of
claims. let the mean of [itex] X_i [/itex] be [itex] \mu_X [/itex] and let the mean of [itex] N [/itex] be [itex] \mu_N [/itex]. Let the variance of [itex] N [/itex] be [itex] \sigma^2_N [/itex]. .

a) show that [itex] E(NS)=\mu_X ( \mu^2_N + \sigma^2_N ) [/itex] by considering expected values
conditional on the value of [itex] N [/itex]

b) hence derive an expression for the covariance between [itex] S [/itex] and [itex]N [/itex].
 

Related to Deriving Covariance between S and N: E(SN) - ìXìN

1. What is the formula for deriving covariance between S and N?

The formula for deriving covariance between S and N is E(SN) - ìXìN, where E(SN) is the expected value of the product of S and N, and ìX and ìN are the respective means of S and N.

2. How is covariance calculated?

Covariance is calculated by finding the expected value of the product of the deviations of each variable from their respective means.

3. What does a positive covariance between S and N indicate?

A positive covariance between S and N indicates a direct relationship, meaning that as one variable increases, the other also tends to increase.

4. How is covariance useful in data analysis?

Covariance is useful in data analysis because it measures the strength and direction of the linear relationship between two variables, allowing for better understanding and prediction of their behavior.

5. Can covariance be negative?

Yes, covariance can be negative. A negative covariance between S and N indicates an inverse relationship, meaning that as one variable increases, the other tends to decrease.

Similar threads

  • Set Theory, Logic, Probability, Statistics
Replies
9
Views
1K
  • Set Theory, Logic, Probability, Statistics
Replies
1
Views
849
  • Set Theory, Logic, Probability, Statistics
Replies
1
Views
2K
  • Set Theory, Logic, Probability, Statistics
Replies
9
Views
2K
  • Set Theory, Logic, Probability, Statistics
Replies
2
Views
878
  • Set Theory, Logic, Probability, Statistics
Replies
2
Views
2K
  • Set Theory, Logic, Probability, Statistics
Replies
14
Views
1K
  • Set Theory, Logic, Probability, Statistics
Replies
3
Views
2K
  • Set Theory, Logic, Probability, Statistics
Replies
1
Views
844
  • Set Theory, Logic, Probability, Statistics
Replies
7
Views
1K
Back
Top