- Thread starter
- #1

- Thread starter dwsmith
- Start date

- Thread starter
- #1

- Feb 13, 2012

- 1,704

If $\displaystyle v_{\perp}$ is the radial speed is $\displaystyle v_{\perp}= r\ \dot{\nu}$ where $\nu$ is the angle in radians...Why is this true?

$$

h = rv_{\perp} = r(r\dot{\nu})\Rightarrow\dot{\nu} = \frac{h}{r^2}

$$

Look at the last page here to see a visualization.

Kind regards

$\chi$ $\sigma$

- Thread starter
- #3

Wouldn't $v_{\perp}$ be the tangential speed? $v_r$ I would think is the radial speed.If $\displaystyle v_{\perp}$ is the radial speed is $\displaystyle v_{\perp}= r\ \dot{\nu}$ where $\nu$ is the angle in radians...

Kind regards

$\chi$ $\sigma$