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#### DeusAbscondus

##### Active member

- Jun 30, 2012

- 176

For some reason, the following does not make sense to me:

If 1. $$f(x)=ln(sin(5x))$$ then 2. $$f'(x)=5cot(5x)$$ but I can only get as far as

$$f(x)=ln(sin(5x))\implies\frac{1}{u}*5cosx=\frac{5cos(x)}{sin(5x)}$$

Can someone please show me how to get from here to 2.? Thanks kindly, DeusAbs