Density parameter and curvature index

In summary, the value of κ is not completely dependent on the value of Ω, but rather follows from it and has the same sign as Ω-1. The definition of κ has multiple options, such as the (-1,0,1) option, which simplifies the question. For more information, see the General Metric section of Friedmann-Lemaître-Robertson-Walker metric on Wikipedia.
  • #1
Ranku
412
18
For Ω=1, κ=0. Does the value of κ simply follow from the value of Ω, or can its value have an independent existence? So if Ω>1, does κ have to be 1?
 
Space news on Phys.org
  • #2
Context would be useful. I don't want to guess what you mean.
 
  • #3
Ranku said:
So if Ω>1, does κ have to be 1?
Yes, by definition. Since Ω=1 is the critical density - the density at which the universe is flat - any other value of Ω necessitates that the k parameter is not 0 and has the same sign as Ω-1.
 
  • Informative
  • Like
Likes Jaime Rudas and Ranku
  • #4
Define k for me.
 
  • #6
The definition of k seems to have more than one option. For example the (-1,0,1) option simplifies your question.
 

Similar threads

  • Cosmology
Replies
9
Views
606
  • Cosmology
Replies
9
Views
2K
  • Cosmology
Replies
3
Views
1K
Replies
22
Views
820
  • Cosmology
Replies
7
Views
1K
Replies
7
Views
839
Replies
2
Views
1K
Replies
6
Views
964
Replies
70
Views
3K
Replies
14
Views
2K
Back
Top