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- #1

express (sqrt(2)/2 + sqrt(2)/2 i)^8 in a+bi form

I know r=1 and tangent=pi/4

Using the theorem i get 1(cos (2pi) +i*sin (2pi)) which becomes 1(1*i)=1*i however WebAssign says this is incorrect. I've also tried "0+1i" and just "i"

What am I doing wrong?