Simple pendulum and angular position

In summary, the conversation is about the speaker's experience in their DE class and their interest in deriving equations related to a simple pendulum from their physics class. They mention a specific equation and ask for help on how to solve it. They also mention their limited math skills and express their curiosity about the topic.
  • #1
Will
Okay, I just took the final for my first DE class! I really liked it, now I can actually know how to derive some of these equations that they just hand to you in physics and chemistry.
So anyway, there is the solution to the angular position(from vertical)of the simple pendulum; the one example we had from class(physics) was theta(t)=Theta-max[e^(-bt/2m)], but i think that the cos(omega*t+phase change) part was ommited?
So I am really interested in deriving this! So I know the motion of the pendulum is given by the diffy Q I(alpha)+b(omega)+g(theta)/L=0 where sin theta has been replace by theta because of small angle approximation, and omega and alpha are the 1st and 2nd derivatives of theta(t). So then what?. Do I solve the aux eq r^2I +rb+g/L or what? Am I on the right track?
This is for my own curiosity only, Uhh please don't tell me to "go study my book a little better" heh heh. Hell even my physics prof. would flounder trying to explain, and dudes got a doctoral degree! Like I said, we are not expected to derive these, but enquiring minds want to know! Thanks
 
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  • #2
oh god, I can't interpret your formulae in my current state

Anywayz, I think I know how to solve the problem you're talking about

If you say that the sum of forces is: Spring - Gravity - Damping you get: (saying that damping is directly proportional to speed) (X is displacement)
Net_Force = Spring_Constant*X - Weight - Damping_Constant*dX/dT
Net_Force = Mass*Acceleration
Acceleration = second derivative of X with respect to time, dX^2/d^2T
And that gives you:

Mass*dX^2/d^2T + Damping_Constant*dX/dT - Spring_Constant*X + Weight = 0

Which appears to be a linear second-order differential equation that you could solve, I'm sure

Unless you're talking about the pendulum deal where you don't say that sin(theta) =~ theta.. My Mathematics level is only a 16, unfortunately, so I can't solve that

I've heard that it can be modeled with some sort of fancy mathematical shape and fancy nonlinear differential equations-solving, but I'm afraid I can take you no farther than that
 
  • #3


Congratulations on taking your first DE (differential equations) class and for being interested in deriving equations rather than just accepting them as given! That is a great mindset to have in the fields of physics and chemistry.

You are on the right track in terms of deriving the equation for the angular position of a simple pendulum. The equation you mentioned, theta(t)=Theta-max[e^(-bt/2m)], is the solution to the differential equation you mentioned, which is known as the "damped harmonic oscillator" equation. This equation takes into account the damping (b), the mass (m), and the length (L) of the pendulum, as well as the acceleration due to gravity (g).

In order to derive this equation, you will need to solve the auxiliary equation, which is r^2I +rb+g/L=0, as you mentioned. This will give you the characteristic equation, which will then allow you to find the roots (or solutions) for r. These solutions will then be used to find the general solution for theta(t), which can then be simplified to the form you mentioned.

It is great that you are curious and want to know more about the derivation of this equation. Keep up the good work and keep exploring and asking questions. That is the best way to learn and deepen your understanding. Good luck in your studies!
 

1. What is a simple pendulum?

A simple pendulum is a weight suspended from a fixed point by a string or rod. It is commonly used as a model system in physics to study the motion of a pendulum and its relationship with the force of gravity.

2. What is the formula for the period of a simple pendulum?

The formula for the period of a simple pendulum is T = 2π√(l/g), where T is the period (time for one full swing), l is the length of the pendulum, and g is the acceleration due to gravity. This formula assumes small angles of swing and a uniform gravitational field.

3. How does the length of a simple pendulum affect its period?

According to the formula for the period of a simple pendulum, the period is directly proportional to the square root of the length. This means that a longer pendulum will have a longer period, and a shorter pendulum will have a shorter period.

4. What is the relationship between angular position and the period of a simple pendulum?

The angular position of a simple pendulum is directly related to its period. As the pendulum swings back and forth, it moves through an arc of a circle, and the time it takes to complete one full swing is the period. The angular position can also be described as the angle at which the pendulum is displaced from its resting position.

5. How does the amplitude of a simple pendulum affect its period?

The amplitude (maximum displacement from equilibrium) of a simple pendulum does not affect its period as long as the angle of swing remains small. This is because the formula for the period assumes small angles of swing, and for small angles, the amplitude does not significantly impact the period.

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