- #1
hitman0097
- 31
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Homework Statement
Consider the resistor network shown in the figure below, where R1= 5[tex]\Omega[/tex] and R2= 7[tex]\Omega[/tex] .
(a) Find the equivalent resistance between points a and b
Req=([1/6 +1/5]+7)+12+6=(9.73)-1+18-1=6.32[tex]\Omega[/tex]
(b) If the potential drop between a and b is 12 V, find the current in each resistor.
I12[tex]\Omega[/tex]=I6[tex]\Omega[/tex]upper=12/18=2/3A
I6[tex]\Omega[/tex]lower=.56A
I5[tex]\Omega[/tex]=?
I7[tex]\Omega[/tex]=?
Homework Equations
Req=V/(Inet)
I=V/R; resistor in parallel I/2
The Attempt at a Solution
For I6[tex]\Omega[/tex]lower I think I just did V/11[tex]\Omega[/tex] and rounded.
Now for I5[tex]\Omega[/tex] shouldn't it be .53A or the same .56A they both got marked wrong though...
And for I7[tex]\Omega[/tex] shouldn't it be .56A+I5[tex]\Omega[/tex]
wrong answers for I7[tex]\Omega[/tex]:.92A,.615A, 1.09A,.67A I have one more attempt. I want to make it count.
wrong answers for I5[tex]\Omega[/tex]:.56A, 1.23A,.53A 2 more tries.
which I think is more important.
Also the total I would be 1.899A?