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- Feb 14, 2012

- 3,802

- Thread starter anemone
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- #1

- Feb 14, 2012

- 3,802

- Jan 30, 2018

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Subtracting the first from the second, 231469a+ 3461b+ 53c= 1. Since a, b, and c are integers that is a linear Diophantine equation.

- Mar 31, 2013

- 1,331

or $(62-19)(a(62^2 + 62 * 19 + 19^2) + b(62+ 19) +c) = 1$

LHS is a multiple of 43 and RHS is 1 so this does not have integer solution

- Mar 31, 2013

- 1,331

because this is a challenge question you are required to answer it fully . this is not a question for help

Subtracting the first from the second, 231469a+ 3461b+ 53c= 1. Since a, b, and c are integers that is a linear Diophantine equation.