- #1
binbagsss
- 1,259
- 11
As we can not meaningfully compare a vector at 2 points acted upon by this operator , because it does not take into account the change due to the coordinate system constantly changing, I conclude that the elementary differential operator must describe a change with respect to space-time,
How do we know that the elementary differential operator does this, instead of describing a change wrt a coordinate system?
Thanks in advance.
How do we know that the elementary differential operator does this, instead of describing a change wrt a coordinate system?
Thanks in advance.