Covariant derivative for four velocity

In summary, the conversation discusses the equation U^a \nabla_a U^b = 0 and the attempt at a solution involves the 4-velocity U^a and Christoffel symbol in Minkowski space. The final result is uncertain, as the 4-acceleration may not necessarily be zero.
  • #1
Kyrios
28
0

Homework Statement


Show [itex] U^a \nabla_a U^b = 0 [/itex]

Homework Equations


[itex] U^a [/itex] refers to 4-velocity so [itex] U^0 =\gamma [/itex] and [itex] U^{1 - 3} = \gamma v^{1 - 3} [/itex]

The Attempt at a Solution



I get as far as this:

[itex] U^a \nabla_a U^b = U^a ( \partial_a U^b + \Gamma^b_{c a} U^c) [/itex]
And I think that the Christoffel symbol is 0 in minkowski space so that gives:
[itex] U^a \partial_a U^b [/itex]

And I'm not certain what to do from this point
 
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  • #2
Is this the problem statement exactly as given. At face value it just looks like the 4-acceleration which by no means needs to be zero.
 
  • #3
Yes this is all that was given, unfortunately, so I'm having trouble explaining why exactly it is zero
 

Related to Covariant derivative for four velocity

1. What is the definition of covariant derivative for four velocity?

The covariant derivative for four velocity is a mathematical tool used in general relativity to describe the change in the four velocity of a particle as it moves along a curved spacetime manifold. It takes into account the curvature of spacetime and is essential for accurately describing the motion of particles in gravitational fields.

2. How is the covariant derivative for four velocity calculated?

The covariant derivative for four velocity is calculated using the Christoffel symbols, which are derived from the metric tensor of the spacetime manifold. The formula for calculating the covariant derivative of a vector is a bit complex, but it essentially involves taking the partial derivatives of the vector components and subtracting out terms involving the Christoffel symbols.

3. What is the physical significance of the covariant derivative for four velocity?

The covariant derivative for four velocity is physically significant because it allows us to properly describe the motion of particles in a curved spacetime. In general relativity, gravity is seen as a manifestation of the curvature of spacetime, and the covariant derivative takes this curvature into account when calculating the change in a particle's velocity. This is crucial for accurately predicting the motion of objects in gravitational fields.

4. How does the covariant derivative for four velocity relate to the geodesic equation?

The geodesic equation is a fundamental equation in general relativity that describes the path of a free-falling particle in a gravitational field. The covariant derivative for four velocity is used in the geodesic equation to account for the curvature of spacetime and accurately predict the motion of particles in a gravitational field.

5. Can the covariant derivative for four velocity be generalized to other types of vectors?

Yes, the covariant derivative can be generalized to other types of vectors, such as higher-order tensors. In general relativity, the covariant derivative is used to describe the change in any type of tensor field as it moves along a curved spacetime manifold. It is a powerful tool for accurately describing the effects of gravity on physical systems.

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