Coulometric vitamin C Titration, pretty basic

[Spirochete]

These questions relate to the secondary coulometric titration of vitamin C. In this titration an applied voltage is used to generate a current that oxidizes Iodide to iodine. Iodine then oxidizes vitamin C. A starch indicator detects excess iodine via the formation of I₃^-

My questions are:

1) What direction does the current flow in this type of experiment? I would think from the voltage source, to the anode, then to the cathode then to the amperometer (sp?) then back to the voltage source?

2) What is happening at the cathode here? I know at the anode Iodide is oxidized. But I can't figure out what's going on at the cathode.

3) If the leads are reversed, what happens at the anode? No idea about this one.

 

[chemisttree]

Electrons are pulled from the iodide into the circuit while the same number of electrons are delivered back into the solution. The process is not spontaneous so the cell is not a galvanic cell but is instead an electrolytic cell. Remember, the current flows in the opposite direction as the electrons.

As to what happens at the electrode opposite the one where iodide is oxidized to iodine, you need to determine what, in solution, is available to accept an electron?

Hint: remember that this experiment is used to determine ascorbic acid.

 

[Blueshift5]

I can provide answers to your questions about coulometric vitamin C titration.

1) In this type of experiment, the current flows from the voltage source to the anode, then to the cathode, and finally to the ammeter before returning to the voltage source. This is known as the conventional current flow direction.

2) At the cathode, reduction reactions occur. In this specific titration, the cathode is where the iodine is reduced back to iodide ions. This is necessary for the titration to continue as it regenerates the iodide ions needed for the oxidation of vitamin C.

3) If the leads are reversed, the anode becomes the cathode and vice versa. This would result in the reduction of vitamin C instead of the oxidation, which would not produce accurate results for the titration. Therefore, it is essential to ensure that the leads are correctly connected to maintain the correct flow of current and reactions at the anode and cathode.

I hope this helps clarify your questions about the coulometric vitamin C titration. Let me know if you have any further inquiries.