Cosmic microwave background fits the blackbody radiation spectrum

In summary, the cosmic microwave background is well described by blackbody radiation with a temperature of 2.7 K and peak wavelength of 1.9nm. Using the relationship between radiant emittance and photon energy density, the number of CMB photons per \mathrm{cm}^3 can be estimated. In regards to high energy cosmic rays, their max energies on Earth are limited by collisions with CMB photons. This leads to a GZK cut-off at a certain energy threshold, which can be determined using the masses of the proton and Delta baryons. The reaction ##p+\gamma\rightarrow\Delta^+## can occur at high energies, causing the observed proton energy on Earth to decrease. However, this process
  • #1
rbwang1225
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0

Homework Statement


(a)The cosmic microwave background fits the blackbody radiation spectrum well with a temperature of 2.7 K and a corresponding peak wavelength at 1.9nm. Applying the relationship between the radiant emittance, i.e. the total power emitted per unit area, and the photon energy density for the blackbody radiation to estimate the number of CMB photons per [itex]\mathrm{cm}^3[/itex] in outer space.

(b) The high energy cosmic rays are believed to be mostly protons and the max energies observed on Earth seem to have a bound. This upper bound is explained by collisions between the high energy protons traveling from extra-galactic space and the CMB photons. If the proton energy is high enough and exceed a threshold value, the following process could occur [itex]p+\gamma\rightarrow\Delta^+, \Delta^+\rightarrow p\pi^0\text{ (or }n\pi^0\text{)}[/itex]. Therefore, the proton energy observed on Earth is decreased and there exists a so called GZK cut-off. Please determine this energy threshold in eV. The masses of the proton and [itex]\Delta[/itex] baryons are about 938Mev/c^2 and 1232 MeV/c^2.

The Attempt at a Solution


Is the answer of (a) be [itex]\sigma T^4/hc^2/\lambda[/itex]?
I have no idea about (b).
Any help would be appreciated.
 
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  • #2


rbwang1225 said:

Homework Statement


(a)The cosmic microwave background fits the blackbody radiation spectrum well with a temperature of 2.7 K and a corresponding peak wavelength at 1.9nm. Applying the relationship between the radiant emittance, i.e. the total power emitted per unit area, and the photon energy density for the blackbody radiation to estimate the number of CMB photons per [itex]\mathrm{cm}^3[/itex] in outer space.

(b) The high energy cosmic rays are believed to be mostly protons and the max energies observed on Earth seem to have a bound. This upper bound is explained by collisions between the high energy protons traveling from extra-galactic space and the CMB photons. If the proton energy is high enough and exceed a threshold value, the following process could occur [itex]p+\gamma\rightarrow\Delta^+, \Delta^+\rightarrow p\pi^0\text{ (or }n\pi^0\text{)}[/itex]. Therefore, the proton energy observed on Earth is decreased and there exists a so called GZK cut-off. Please determine this energy threshold in eV. The masses of the proton and [itex]\Delta[/itex] baryons are about 938Mev/c^2 and 1232 MeV/c^2.

The Attempt at a Solution


Is the answer of (a) be [itex]\sigma T^4/hc^2/\lambda[/itex]?
I don't know if your expression is anywhere near correct, but I just wanted to ask if you meant
##\sigma T^4/(hc^2/\lambda)## or ##(\sigma T^4/hc^2)/\lambda##.

Explain how you came up with your answer.

I have no idea about (b).
Any help would be appreciated.
You're asked to find the energy threshold. Why would ##p+\gamma\rightarrow\Delta^+## happen at some energies and not others?

By the way, ##\Delta^+ \to n\pi^0## violates conservation of charge. It can't happen. Perhaps you meant ##\Delta^+ \to n\pi^+##.
 

Related to Cosmic microwave background fits the blackbody radiation spectrum

1. What is cosmic microwave background (CMB) radiation?

Cosmic microwave background (CMB) radiation is the residual thermal energy from the Big Bang that permeates the entire universe. It is the oldest light in the universe and is essentially the afterglow of the Big Bang.

2. What is the blackbody radiation spectrum?

The blackbody radiation spectrum is a curve that shows the distribution of radiation emitted by an object at different wavelengths and temperatures. It follows a specific mathematical equation and is often used to describe the CMB radiation.

3. How does the CMB radiation fit the blackbody radiation spectrum?

The CMB radiation has been found to fit the blackbody radiation spectrum with an extremely high level of accuracy. This means that the CMB radiation has a perfect thermal spectrum, indicating that it is in thermal equilibrium and has not been significantly affected by any other processes since the Big Bang.

4. What does the CMB radiation tell us about the early universe?

The CMB radiation provides us with valuable information about the early universe, such as its age, composition, and initial conditions. By studying the fluctuations in the CMB radiation, scientists can also learn about the structure and evolution of the universe.

5. How is the CMB radiation measured?

The CMB radiation can be measured using specialized instruments called microwave telescopes. These telescopes are designed to detect and measure the faint microwave radiation emitted by the CMB. The most famous instrument used for measuring the CMB is the Planck satellite, which has provided us with the most precise measurements of the CMB to date.

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