- Thread starter
- #1

- Thread starter Elissa89
- Start date

- Thread starter
- #1

- Mar 1, 2012

- 644

$r = \dfrac{1}{1+\sin{\theta}}$The equation is:

r= 1/1+sin(theta)

I know the answer is supposed to be:

x^2+y^2=(1-y)^2

I can't figure out the steps to get to the answer.

divide both sides by $r$ ...

$1 = \dfrac{1}{r+r\sin{\theta}} \implies r+r\sin{\theta} = 1$

$r + y = 1$

$r = 1 - y$

can you finish?

- Thread starter
- #3

Yes Thanks$r = \dfrac{1}{1+\sin{\theta}}$

divide both sides by $r$ ...

$1 = \dfrac{1}{r+r\sin{\theta}} \implies r+r\sin{\theta} = 1$

$r + y = 1$

$r = 1 - y$

can you finish?