Either there's a typo somewhere or this is too simple a problem.Convert the equation to polar form
I thought it would be
Said it was incorrect
then I thought I needed to divide by 8 to remove it, giving me:
But that was also incorrect and now I am stuck
Nope, no typo. I also tried cos(theta)=sin(theta). Then I thought I need to get the r alone and I got r=r*tan(theta)Either there's a typo somewhere or this is too simple a problem.
Your difficulty is that you stopped too soon. You can also divide by r (assuming that it's not zero). Thus you have the equation: \(\displaystyle cos( \theta ) = sin( \theta )\). There are several possible values for \(\displaystyle \theta\).
Any Cartesian line of the form:I tried inputting pi/4 and 5pi/4, but it doesn't want an answer, it wants the question converted to a polar equation.
Yes, it didn't take itAny Cartesian line of the form:
will correspond to a polar equation of the form:
Only a line not passing through the origin will have a polar equation involving both \(r\) and \(\theta\).
Did you try inputting:
\(\displaystyle \tan(\theta)=1\) ?