- Thread starter
- #1

\(\displaystyle T_{n}(x)=(2^{-1}x_{1},....,2^{-n}x_{n},0,0,....). \)Show that \(\displaystyle T_{n}->T\) given by

\(\displaystyle T(x)==(2^{-1}x_{1},2^{-2}x_{2},0,0,....). \)

I get a sequence of geometric series as my answer for the norm, but not sure whether that's correct.