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*Determine whether the integral is Divergent or Convergent*\(\displaystyle \int^0_{-\infty} \frac{1}{3 - 4x} dx\)

I did a

**substitution and got**

*u*\(\displaystyle \lim_{a\to\infty} -\frac{1}{4}\sqrt{3} + \frac{1}{4}\sqrt{3 - 4a}\)

So is because the \(\displaystyle -\infty\) is under the square root is it going to be

**?**

*divergent*I have \(\displaystyle \frac{1}{4}\sqrt{3 - 4\infty}\)

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