- #1
duarthiago
- 11
- 0
I've read that the total forward force on an engine is given by a change of momentum which is written as ##P = \mu_{fuel}v_{0} + \mu_{air}(v_{0}-v) ##, where ##\mu_{fuel}##, ##\mu_{air}##, ##v_{0}## and ##v## are respectively the rate of decrease of mass of the fuel being burnt, the rate which the air is being carried through the engine, the velocity of the material ejected by the engine and finally the velocity of the aircraft.
The book where I read it says that "The main function of the fuel that is carried with the plane is to give the ejected gases a high speed with respect to the plane, and most of the moving mass is supplied by the air" but I really don't understood it, I mean, I can't visualize it. I would to know what that ##\mu_{air}(v_{0}-v)## physically means. I thought the change of momentum was due only by the fuel burnt.
The book where I read it says that "The main function of the fuel that is carried with the plane is to give the ejected gases a high speed with respect to the plane, and most of the moving mass is supplied by the air" but I really don't understood it, I mean, I can't visualize it. I would to know what that ##\mu_{air}(v_{0}-v)## physically means. I thought the change of momentum was due only by the fuel burnt.