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**Re: mean proportion problem**

if a,b,c are in continued proportion

prove that

(a+b+c)^2/(a^2 +b^2 + c^2)=(a+b+c)/(a-b+c)

i break the part -> (a+b+c)^2 in to (a^2 +b^2+c^2+2ab+2bc+2ac) and then use componendo dividendo to the numerator and denominator to the problem,,, but its still not working out .wondering how to solve it . please help !!!