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Kurokari
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Homework Statement
Two bodies P and Q of different masses on a smooth table are connected by a light elastic string which is stretched. P and Q are then released.
Which of the following is of the same magnitude for both P and Q
Speed, Acceleration, Momentum, Distance moved.
Answer: Momentum
Homework Equations
m1v1 + m2v2 = m1u1 + m2u2
The Attempt at a Solution
Since both bodies are at rest first, so initial velocity for both are 0.
This makes m1v1 + m2v2 = 0, m1v1 = - m2v2
My concern is that, since the question stated that both the bodies P and Q have different masses, so this must mean that in the equation m1v1 = - m2v2, the velocity v1 and v2 is different. The question does not mention anything about the length of the string extension, so I assume that it's the same length for both bodies P and Q.
Ok here's the deal, does this mean that velocity is somehow influence by the mass, like a ratio thing seeing how the equation can be expressed in a ratio form only with a negative sign.
If so, does this apply in a general sense, or only towards this case which is conservation of momentum.
or am I thinking far far away and has gotten it all wrong? :D