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Wara
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Elastic Potential Energy with Spring and Incline (Diagram Included)
ET = 1/2(m)(V2) + mgh + 1/2k*x2
ET1 - Wf = ET2
1/2k*x2 - Wf = mgh + 1/2mV2
where, Wf = [(0.53)(2kg)(9.8m/s2)(cos67)](1.3m+0.4m)
^ I used this formula and went through by subbing in all numbers but I get error since you can't square root a negative value. Plus we can assume Height off ground is negligible since it cancels out on both sides of equation.
Homework Statement
Homework Equations
ET = 1/2(m)(V2) + mgh + 1/2k*x2
The Attempt at a Solution
ET1 - Wf = ET2
1/2k*x2 - Wf = mgh + 1/2mV2
where, Wf = [(0.53)(2kg)(9.8m/s2)(cos67)](1.3m+0.4m)
^ I used this formula and went through by subbing in all numbers but I get error since you can't square root a negative value. Plus we can assume Height off ground is negligible since it cancels out on both sides of equation.
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