- #1
Michael V
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Homework Statement
The following information applies to a conical diffuser:
Length = 750 mm
Inlet diameter = 100 mm
Outlet diameter = 175 mm
Water flow = 50 l/s
Pressure at inlet = 180 kPa
Friction loss = [itex]\frac{k(V_{1} - V_{2})^{2}}{2g}[/itex] where k = 0.15
Calculate the pressure at exit. (10)
The same diffuser is then installed in a vertical pipeline where the flow is now downward and the quantity of water flow is to be double the above flow. The inlet pressure in the diffuser inlet (smaller diameter) is 150 kPa. Consider friction loss and calculate the pressure at the exit of the
diffuser. (10)
Homework Equations
Bernoulli's Equation : [itex]Z_{1}+\frac{P_{1}}{ρg}+\frac{V_{1}^{2}}{2g}[/itex] = [itex]Z_{2}+\frac{P_{2}}{ρg}+\frac{V_{2}^{2}}{2g}+H_{loss}[/itex]
The Attempt at a Solution
The 1st part of the question is not a problem where [itex]Z_{1}[/itex]= [itex]Z_{2}[/itex]. The problem I'm having is when it becomes vertical does [itex]Z_{1}[/itex]or [itex]Z_{2}[/itex] = 0.75m.
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