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#### skatenerd

##### Active member

- Oct 3, 2012

- 114

$$Ccos(\omega_{o}t-\phi)=Asin(\omega_{o}t)+Bcos(\omega_{o}t)$$

This proved to be a bit more difficult than I expected, so I looked up a complete list of trig identities.

$$cos(a\pm{b})=cos(a)cos(b)\mp{sin(a)sin(b)}$$

seems like the only one that could be helpful in my situation, however when I try to think of a way where the original equation makes sense, I am really not able to convince myself.

Wouldn't the only way for the original equation to make sense be if

\(sin(\phi)=cos(\phi)=1\)? As far as I know this is only possible for \(\frac{-3\pi}{4}\).

Kind of stuck here, any help would be very appreciated