Conceptual Question on acceleration and circular motion

In summary, the textbook's solution is to use the normal force of the loop and the force of gravity to create a centripetal force which is less than the acceleration of gravity. When the normal force equals zero, that's the minimum speed at which the car will stay on the track.
  • #1
RoboNerd
410
11

Homework Statement


If a roller coaster car enters the circular-loop portion of the ride and navigates it successfully, then the net force on the car at its topmost point is straight down. Then why does not the car fall down?

So I am having issues understanding my textbook's solution to the conceptual problem above.

The textbook's solution is as following:
"Remember that force tells an object how to accelerate. If the car had zero velocity at this point, then it would certainly fall straight down, but the car has a non-zero velocity to the left at this point. The fact that acceleration is downward means that at the next moment, vector v will point down to the left at a slight angle, ensuring that the car remains on a circular path, in contact with the rack. The minimum centripetal acceleration of the car at the top of the track would be equal to the acceleration of gravity, g = 9.8 m/s^2. If centripetal acceleration were less than g, then the car would fall off its circular path."

Homework Equations


F[c][/SUB]=m*a[c][/SUB]

The Attempt at a Solution


I understand the portion of the solution where they say that the acceleration would cause the direction of the leftward velocity vector to move downwards. However, I do not understand why they say that the minimum centripetal acceleration of the car at the top of the track would be equal to the acceleration of gravity and if acceleration of gravity would be greater than centripetal acceleration, the car would fall off.

Could someone please help me understand this?

Thanks in advance!
 
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  • #2
Try this: Imagine that the car is speeding around the loop (way faster than the minimum speed). At the top of the loop, what forces act on the car?
 
  • #3
The normal force of the loop and the force of gravity.

Yes, I know that.
 
  • #4
RoboNerd said:
The normal force of the loop and the force of gravity.
Right, and those forces add to produce the centripetal force.

What happens to those forces as the speed of the car is reduced?
 
  • #5
Doc Al said:
Right, and those forces add to produce the centripetal force.

What happens to those forces as the speed of the car is reduced?
Gravity remains constant. Normal force decreases
 
  • #6
RoboNerd said:
Gravity remains constant. Normal force decreases
Right. As the speed decreases, the needed centripetal force decreases. When the normal force equals zero, that's the minimum speed. Go slower and the actual force (gravity) is greater than that needed to keep the car in circular motion. It gets pulled off the track.
 
  • #7
Doc Al said:
Right. As the speed decreases, the needed centripetal force decreases. When the normal force equals zero, that's the minimum speed. Go slower and the actual force (gravity) is greater than that needed to keep the car in circular motion. It gets pulled off the track.
The mass terms in centripetal force and gravity force cancel... so the accelerations matter. Right. Thanks!
 

1. What is the difference between linear acceleration and angular acceleration?

Linear acceleration refers to the change in velocity of an object in a straight line, while angular acceleration refers to the change in angular velocity of an object rotating around a central axis.

2. How is centripetal acceleration related to circular motion?

Centripetal acceleration is the acceleration towards the center of a circle that keeps an object moving in a circular path. It is always perpendicular to the velocity of the object and is necessary for circular motion to occur.

3. Can an object have a constant speed but varying acceleration in circular motion?

Yes, an object can maintain a constant speed while still experiencing varying acceleration in circular motion. This is because acceleration is a vector quantity, meaning it has both magnitude and direction. In circular motion, the direction of the acceleration is constantly changing, even if the speed remains the same.

4. How does the radius of a circle affect the centripetal acceleration of an object?

The centripetal acceleration of an object is directly proportional to the square of the radius of the circle it is moving in. This means that as the radius increases, the centripetal acceleration decreases, and vice versa.

5. What is the relationship between tangential velocity and centripetal acceleration in circular motion?

There is a direct relationship between tangential velocity (the speed at which an object is moving along its circular path) and centripetal acceleration. As the tangential velocity increases, the centripetal acceleration also increases. This is because a higher tangential velocity requires a larger centripetal acceleration to keep the object moving in a circular path.

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